Copper(II) nitrate reacts with sodium hydroxide to produce a precipitate of light blue copper(II) hydroxide. (a) Write the net ionic equation for the reaction. (b) Calculate the maximum mass of copper(II) hydroxide that can be formed when 2.00 g of sodium hydroxide is added to 80.0 mL of
0.500 M Ch(NO3)2 (aq).
In the above problem, we have to be able to know what the spectator ions are in order to solve the problem. Is this something we need to know for the final? If so, can someone explain how to determine what the spectator ions are?
Textbook Question M.9
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SainehaMaddineni_3I
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Re: Textbook Question M.9
Spectator ions don't take part in the chemical reaction to form a precipitate. By looking at the product, you can differ which are the spectator ions.
For example, Cu(NO3)2 + NaOH --> Cu(OH)2. In this equation, you can see that Na^+ and NO3^- are not involved in creating the final product of the precipitate. Therefore, those are the spectator ions.
For example, Cu(NO3)2 + NaOH --> Cu(OH)2. In this equation, you can see that Na^+ and NO3^- are not involved in creating the final product of the precipitate. Therefore, those are the spectator ions.
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