On question 3 of the Dino Nuggets it asks:
"Ammonia (NH3) reacts with oxygen (O2) to form air pollutant nitrogen oxide (NO) and water. Determine the theoretical yield of NO is 21.1g NH3 is reacted with 42.2g O2?"
Can anyone walk me through how to do this because I thought I knew what I was doing but I haven't been able to get the correct answer.
Thank you!
Dino Nuggets Question 3
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Re: Dino Nuggets Question 3
first you should balance the equation, this way you can see the molar ratios of all compounds involved. Then, perform stoichiometric conversions for both the O2 and the NH3 into NO. The theoretical yield will be the smallest amount of NO that is calculated, as this reactant is also the limiting reactant.
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Re: Dino Nuggets Question 3
I'm having a little trouble figuring out what the limiting reactant would be
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Re: Dino Nuggets Question 3
First, the equation-- 2NH3 + 4O2 -> 2NO + 3H20
Using stoichiometry, convert grams of ammonia into mols and then use the ratio of reactant to product to find the mol of NO produced.
21.1g NH3 * 1mol/ 17.03g NH3 = 1.2389 mol * 2mol NO/ 2mol NH3 = 1.23mol NO
Do the same for water, and you should get around 0.659 mol, which is the theoretical yield.
Using stoichiometry, convert grams of ammonia into mols and then use the ratio of reactant to product to find the mol of NO produced.
21.1g NH3 * 1mol/ 17.03g NH3 = 1.2389 mol * 2mol NO/ 2mol NH3 = 1.23mol NO
Do the same for water, and you should get around 0.659 mol, which is the theoretical yield.
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