"Consider the following imbalanced reaction: PCl3+ H2O —->HCl + H3PO3. What quantity of HCl is generated when 23.6g of PCl3 reacts?"
I think it would be a 1:3 ratio, however, I am unsure.
Balance Reaction
Moderators: Chem_Mod, Chem_Admin
-
- Posts: 102
- Joined: Fri Sep 24, 2021 5:24 am
Re: Balance Reaction
Since the balanced equation is PCl3 + 3H2O -> 3HCl + H3PO3, I think your ratio is correct!
-
- Posts: 95
- Joined: Fri Sep 24, 2021 7:33 am
Re: Balance Reaction
Yes, the balanced equation would be PCl3+ 3H2O —->3HCl + H3PO3 creating a 1:3 ratio for PCl3:HCl in moles. You can't use this ratio, however, until you convert the grams given into moles.
Re: Balance Reaction
Hi!
For this question we first have to balance the reaction, leaving us with the following balanced reaction:
PCl3 + 3H2O --> 3HCl + H3PO3.
Then, we have to convert 23.6g of PCl3 to moles by dividing 23.6 by the molar mass of the molecule (137.33 g/mol). Then, using the molar ratio we see from the equation (1 PCl3: 3 HCl) we can find out the amount, in moles, of HCl that will be produced. Finally, we can convert the number of moles of HCl into grams by multiplying it with the molar mass of HCl (36.46 g/mol). Hope this helps!
For this question we first have to balance the reaction, leaving us with the following balanced reaction:
PCl3 + 3H2O --> 3HCl + H3PO3.
Then, we have to convert 23.6g of PCl3 to moles by dividing 23.6 by the molar mass of the molecule (137.33 g/mol). Then, using the molar ratio we see from the equation (1 PCl3: 3 HCl) we can find out the amount, in moles, of HCl that will be produced. Finally, we can convert the number of moles of HCl into grams by multiplying it with the molar mass of HCl (36.46 g/mol). Hope this helps!
-
- Posts: 109
- Joined: Fri Sep 24, 2021 5:23 am
Re: Balance Reaction
The ratio would be 1:3 for PCl3: 3 HCl. To find the amount of moles of a reactant, you would divide the given grams by the molar mass. Hope this helped!
-
- Posts: 102
- Joined: Fri Sep 24, 2021 5:41 am
Re: Balance Reaction
Yes, for the balanced equation PCl3+ 3H2O —->3HCl + H3PO3, the ratio would be 1:3 for PCl3: 3 HCI. To find the answer, remember to convert the given grams of 23.6 g of PCl3 into moles by dividing it by the molar mass, then use the ratio of 1:3 to find the amount of HCI through the reaction. If it asks for the answer in grams, multiply the number of HCI moles produced by the molar mass to find the number in grams.
-
- Posts: 100
- Joined: Fri Sep 24, 2021 6:47 am
Re: Balance Reaction
Yes, first we balance the equation and get PCl3 + 3H2O --> 3HCl + H3PO3, meaning that you're correct. Next, just convert the 23.6 g of PCl3 into moles, dividing my the molar mass and use the 1:3 ratio to find the amount of HCI.
-
- Posts: 100
- Joined: Fri Sep 24, 2021 7:36 am
Re: Balance Reaction
The ratio you obtained seems right :) You should also remember to convert the given grams of 23.6 g of PCl3 into moles by dividing it by the molar mass, then use the ratio you got (1:3) to find the amount of HCI that was generated by the reaction.
-
- Posts: 101
- Joined: Fri Sep 24, 2021 6:57 am
Re: Balance Reaction
The ratio you have is correct! The only way to make sure would be to balance the equation and see the number of moles of each molecule and it seems like that is what you did here!
-
- Posts: 101
- Joined: Fri Sep 24, 2021 6:26 am
Return to “Limiting Reactant Calculations”
Who is online
Users browsing this forum: No registered users and 4 guests