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8.49

Posted: Sun Jan 24, 2016 4:38 pm
by Katherine Delgadillo 2H
Given:
OF2+H20 = O2+2HF ΔH= -318KJ

What is the change in internal energy for the reaction of 1.00 mol of OF2?

I don't understand why Δn=+1mol and how this ends up changing PV=nRT to PΔV=ΔnRT?

Re: 8.49

Posted: Sun Jan 24, 2016 4:46 pm
by Jeannie Huang 3B
I believe the +1 mol is from 2 mol reactants --> 3 mol products. So change of mols was 3-2 =1.
Other people have posted about this question before so I recommend checking those out :]

Re: 8.49

Posted: Sun Jan 24, 2016 4:50 pm
by Chem_Mod
Also see this post for which ideal gas law equations to apply

viewtopic.php?f=77&t=10319