## Exercise 8.41

$\Delta U=q+w$

trase aguigam 2A
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### Exercise 8.41

I am confused as to why the heat of fusion and specific heat capacity of water must be taken into account to calculate the heat to melt ice at 0 degrees Celsius.

Why is the approach/method applied to exercise 8.21 not applicable in this situation?

Geovanni_Suarez_3A
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Joined: Fri Jul 22, 2016 3:00 am

### Re: Exercise 8.41

Exercises 8.21 and 8.41 are similar except in exercise 8.41 the ice is going through a phase change so you have to calculate the heat required for that to occur (hence using the enthalpy of fusion) along with the heat calculated by using (mass x specific heat x change in temperature) equation.

In 8.21 the copper and water do not go through a phase change so only the (mass x specific heat x change in temperature) equation is needed to calculate heat for each.

trase aguigam 2A
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### Re: Exercise 8.41

That makes sense! Thank you for clarifying!

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