HW 8.117


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Jennifer_Yee_3I
Posts: 9
Joined: Wed Sep 21, 2016 2:58 pm

HW 8.117

Postby Jennifer_Yee_3I » Thu Jan 26, 2017 9:50 pm

One step in the production of hydrogen as a fuel is the reaction of methane with water vapor:
CH4(g) + H20(g) --> CO2(g) + 3H2(g) deltaH= -318 kJ
What is the change in internal energy for the production of 1.00 mol H2?

I'm wondering if someone could clarify why there is a net production of 2/3 mole of gas according to the solutions manual. Where does this come from?
Thank you!

Rochelle Ellison 2H
Posts: 29
Joined: Wed Sep 21, 2016 3:00 pm

Re: HW 8.117

Postby Rochelle Ellison 2H » Fri Jan 27, 2017 10:58 am

The problem is asking for the change in internal energy for 1 mol of H2 but the chemical equation shows the production of 3 mol H2. Therefore, you have to divide each of the stoichiometric coefficients by 3 mol so that the equation reads 1/3CH4(g) + 1/3H2O(g) → 1/3CO2(g) + H2(g). Now you can see that there were 2/3 mol of gas on the reactants side and 4/3 mol on the products side so the net production of gas is 4/3-2/3=2/3 mol.


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