$\Delta U=q+w$

Helen_Lee_1L
Posts: 12
Joined: Wed Sep 21, 2016 3:00 pm

In an adiabatic expansion, the volume goes from 1 Liters to 2.56 Liters at an external pressure of 1 atm. It releases 73J of heat at 1 atm, and returns to its original delta U. Find final volume.

So I understand that in an adiabatic expansion q=0, and so delta U equals work. Therefore, work (w) equals negative external pressure times delta volume. What would I have to do if I have to find the delta U if we are not give the energy?

104733470
Posts: 9
Joined: Wed Sep 21, 2016 3:00 pm