## Accounting for Copper in 8.19

$\Delta U=q+w$

lizzygaines1D
Posts: 52
Joined: Thu Jul 13, 2017 3:00 am

### Accounting for Copper in 8.19

For homework problem #19, you are asked how much heat is needed for a 500.0 g copper kettle with 400.0 g of water inside to raise the temp of the water form 22 degrees C to 100 degrees C. I understand using the q=mC x change in temp, but I'm assuming you have to account for the copper kettle absorbing heat and how do you do that?

Sarah_Stay_1D
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### Re: Accounting for Copper in 8.19

lizzygaines1D wrote:For homework problem #19, you are asked how much heat is needed for a 500.0 g copper kettle with 400.0 g of water inside to raise the temp of the water form 22 degrees C to 100 degrees C. I understand using the q=mC x change in temp, but I'm assuming you have to account for the copper kettle absorbing heat and how do you do that?

All you have to do to account for the heat absorbed by the cooper is add the q(copper) to the q(water).

John Huang 1G
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Joined: Thu Jul 13, 2017 3:00 am
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### Re: Accounting for Copper in 8.19

To account for the heat absorbed the copper kettle, you'll have to use q=(mass of copper)(specific heat of copper)(change in temperature).

To account for both of the heat transfers, just add q(water) and q(copper kettle).