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8.93

Posted: Sun Feb 11, 2018 10:25 pm
by Naomi Jennings 2H
Calculate the work that must be done against the atmosphere for the expansion of the gaseous products in the combustion of 1.00 mol C6H6(l) at 25 degrees C and 1.00 bar.
How would you start to do this problem?

Re: 8.93

Posted: Sun Feb 11, 2018 10:36 pm
by Anh Nguyen 2A
Since the work is done against the atmosphere, the pressure is constant or ΔP=0. In that case, w=-P.ΔV=-P.Δn(gas).R.T
with Δn(gas)=n(gas) products - n(gas) initial