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In the 7th Ed. Section 4A Q13, the problem states "a constant volume calorimeter was calibrated by carrying out a rxn known to release 3.5 kJ if heat in 0.2 L of sol. in the calorimeter (q=-3.50kJ). When calculating C, the solutions manual changed the q from -3.50 kj to + 3.50 kj...why?
the q=-Ccal*deltaT when you are calibrating the calorimeter; q=-q(cal), another way is to note that the specific heat of a calorimeter should not be negative so if you get a negative value you should make it positive. hope this helps!
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