DeltaU=q+w
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DeltaU=q+w
I don't understand why the equation is change in U is equal to q + w. Why is it not change in U is equal to the change in q + the change in w?
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Re: DeltaU=q+w
Both q and w are considered to be change already. Since heat is flowing between the system and surroundings, there is already a change in heat being transferred/absorbed/released. Same applies for work. Work is a broad term, but it's the merely the idea that something is capable of doing stuff. When we look at the equation of -P∆V and -nRTln(V2/V1), there is an area under the curve that is indicative of work with infinitesimal changes. Both q and w already are going through changes, so it isn't necessary to write a delta.
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Re: DeltaU=q+w
q and w are both path functions and both represent transfers of energy between systems and their surroundings.
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