8.41


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Cynthia Ulloa
Posts: 52
Joined: Fri Feb 23, 2018 3:02 am

8.41

Postby Cynthia Ulloa » Sun Feb 10, 2019 10:30 pm

"A 50.0-g ice cube at 0.0 degree C is added to a glass containing 400.0 g of water at 45.0 degree C. What is the final temperature of the system (see Tables 8.2 and 8.3)? Assume that no heat is lost to the surroundings." Can someone tell me how to go about this problem? I know we will have to use nCdeltaT, but how would I take into account the phase changes?

armintaheri
Posts: 68
Joined: Fri Sep 28, 2018 12:26 am

Re: 8.41

Postby armintaheri » Sun Feb 10, 2019 11:52 pm

You would need to use the heat of fusion.

heat gained by ice = heat lost by water
(heat needed to melt ice)(heat needed to warm melted ice)=(heat lost by water)
(heat of fusion for water)(mass of ice)+(mass of melted ice)(heat capacity of water)(x-0)=(mass of water in the glass)(heat capacity of water)(45-x)


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