$\Delta U=q+w$

Celine Hoh 2L
Posts: 66
Joined: Fri Sep 28, 2018 12:28 am

I understand that q=0 in adiabatic situations, but why does w=Cv* deltaT? ( I thought that w is suppose to be work due to expansion of gas)

Angel Chen 2k
Posts: 59
Joined: Fri Sep 28, 2018 12:20 am

Because work can be done in the adiabatic process even though the heat transfer does not exist. According to the first of thermodynamics, thermal energy will also change when work changes and heat does not change. Also, work can make volume changes. It explains the delta V in the equation you mentioned in the question.

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