## q=0

$\Delta U=q+w$

505095793
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### q=0

If a system has adiabatic walls can we assume q=0 and delta U=w?

305113590
Posts: 66
Joined: Fri Sep 28, 2018 12:28 am

### Re: q=0

Yes, this is because since temperature is constant. The equations, C∆T and mC∆T have a change in temperature, but adiabatic is constant temperature. Therefore ∆U only is dependent on work of expansion, w.

Sophia Ding 1B
Posts: 62
Joined: Fri Sep 28, 2018 12:16 am

### Re: q=0

Yes, because if temperature is constant in this type of isolated system, then heat is never lost nor gained. Thus q, heat, is not changing within the system and can be set equal to 0. And because we know that ∆U = q + w, if q = 0 then that leaves ∆U = w.

Ethan Breaux 2F
Posts: 63
Joined: Sat Sep 29, 2018 12:16 am

### Re: q=0

They'll usually just say constant temp or isothermal which is pretty much the same thing.

Jasmine Chow 1F
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### Re: q=0

yes you can assume that q is equal to zero. In this type of reaction, say a piston, the piston moves so quickly it does not allow an exchange of heat with the surroundings therefore there is no heat for an adiabatic system.