## 4B.5 and 4B.13 part a

$\Delta U=q+w$

Jielena_Bragasin2G
Posts: 104
Joined: Sat Aug 24, 2019 12:18 am
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### 4B.5 and 4B.13 part a

In both of these problems I used w=-(Pext)(delta V) to find work but it is given in atm. In the solutions manual it is multiplied by a constant to convert it to joules. Can someone explain to me what constant should I use to convert my answer into joules? Thanks!

Harry Zhang 1B
Posts: 101
Joined: Sat Sep 14, 2019 12:16 am

### Re: 4B.5 and 4B.13 part a

You would use 1L*atm=101.325J. This can be found in a example problem on page 247.

Haley Dveirin 1E
Posts: 101
Joined: Sat Jul 20, 2019 12:17 am

### Re: 4B.5 and 4B.13 part a

So in the case of 4B 5 the units of w are L atm so you have to multiply it by 8.31447 J/mol K and then divide it by 0.08206 L atm/mol K in order to get the units to be J.