Deriving Equation

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Andrew Liang 1I
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Deriving Equation

Postby Andrew Liang 1I » Wed Jan 29, 2020 4:50 pm

How did Dr. Lavelle derive this equation: delta U = delta H - (P delta V)?

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Re: Deriving Equation

Postby DanielTalebzadehShoushtari2A » Wed Jan 29, 2020 4:52 pm

This equation holds true for a situation of constant pressure. Professor Lavelle starts with the equation U = q + w, and q = deltaH in conditions of constant pressure. w becomes -PdeltaV because in gas expansions/compressions, work done on the system is equal to -PdeltaV

Zaynab Hashm 2I
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Re: Deriving Equation

Postby Zaynab Hashm 2I » Wed Jan 29, 2020 6:05 pm

delta U = delta H - P delta V comes from the equation U = q + w

since q = delta H (change in enthalpy), and w = - P delta V,
when you plug those in instead of q and w, you will get delta U = delta H - P delta V

Dina Marchenko 2J
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Joined: Thu Jul 25, 2019 12:16 am

Re: Deriving Equation

Postby Dina Marchenko 2J » Sun Feb 02, 2020 1:21 pm

delta H is plugged in to replace q and -PΔV is plugged in to replace w.

q=ΔH because ΔH represents the heat gain or loss of a system quantitatively.

w=-PΔV because:
you start with force= P(external) x area
-This is the formula for the pressure being exerted by the system
also, the volume of the area expanded is V=area x distance (height gained by work or lost)

w=force x distance and
force= pressure x area so
w=pressure x area x distance
(area x distance is volume so we end up with:)

negative because the system loses energy as it does work

To make a very long story short, it's just about plugging in different values that are established as equal to each other to derive new equations.

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