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Typically the problem will indicate it. For example if the problem gives you delta H at constant pressure then delta H = q or if the problem says explicitly that 50J heat transferred. Or, the problem may have two steps and in one you find w and in the order you use w to find q.
When the volume is constant, w=0. If the problem gives you the amount of energy that increased/decreased (q) after doing a certain amount of work (w) is when you can incorporate both q and w for the change in internal energy.
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