## final review slide 4

$\Delta U=q+w$

kennedyp
Posts: 56
Joined: Tue Nov 13, 2018 12:18 am

### final review slide 4

How does Lavelle find that there is deltan=1 mole of gas when there's 3 moles of gas on the right side of the equation?

kennedyp
Posts: 56
Joined: Tue Nov 13, 2018 12:18 am

### Re: final review slide 4

Actually nvm, I see my mistake now!

lilymayek_1E
Posts: 107
Joined: Sat Aug 17, 2019 12:16 am

### Re: final review slide 4

he finds the net production of gas because there are 3 mols of gas on the right side (products), 2 mols of gas on the left (reactants). Because this is a standard 1.00 mole reaction of O2, meaning the equation presented is what is occurring, you find the total production with a 3-2=1 mole of gas. the change in the amount of gas is +1 mole from reactants to products.

edit whoops i just saw your new message!

kennedyp
Posts: 56
Joined: Tue Nov 13, 2018 12:18 am

### Re: final review slide 4

lilymayek_1E wrote:he finds the net production of gas because there are 3 mols of gas on the right side (products), 2 mols of gas on the left (reactants). Because this is a standard 1.00 mole reaction of O2, meaning the equation presented is what is occurring, you find the total production with a 3-2=1 mole of gas. the change in the amount of gas is +1 mole from reactants to products.

edit whoops i just saw your new message!

Thanks anyways! lol, and this is an awesome explanation in case someone else was confused too!

Owen-Koetters-4I
Posts: 50
Joined: Fri Sep 28, 2018 12:16 am

### Re: final review slide 4

You subtract the mol of gas formed and the mol of gas reacting