final review slide 4


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kennedyp
Posts: 56
Joined: Tue Nov 13, 2018 12:18 am

final review slide 4

Postby kennedyp » Sun Mar 15, 2020 6:53 am

How does Lavelle find that there is deltan=1 mole of gas when there's 3 moles of gas on the right side of the equation?

kennedyp
Posts: 56
Joined: Tue Nov 13, 2018 12:18 am

Re: final review slide 4

Postby kennedyp » Sun Mar 15, 2020 6:54 am

Actually nvm, I see my mistake now!

lilymayek_1E
Posts: 107
Joined: Sat Aug 17, 2019 12:16 am

Re: final review slide 4

Postby lilymayek_1E » Sun Mar 15, 2020 6:58 am

he finds the net production of gas because there are 3 mols of gas on the right side (products), 2 mols of gas on the left (reactants). Because this is a standard 1.00 mole reaction of O2, meaning the equation presented is what is occurring, you find the total production with a 3-2=1 mole of gas. the change in the amount of gas is +1 mole from reactants to products.

edit whoops i just saw your new message!

kennedyp
Posts: 56
Joined: Tue Nov 13, 2018 12:18 am

Re: final review slide 4

Postby kennedyp » Sun Mar 15, 2020 7:59 am

lilymayek_1E wrote:he finds the net production of gas because there are 3 mols of gas on the right side (products), 2 mols of gas on the left (reactants). Because this is a standard 1.00 mole reaction of O2, meaning the equation presented is what is occurring, you find the total production with a 3-2=1 mole of gas. the change in the amount of gas is +1 mole from reactants to products.

edit whoops i just saw your new message!

Thanks anyways! lol, and this is an awesome explanation in case someone else was confused too!

Owen-Koetters-4I
Posts: 50
Joined: Fri Sep 28, 2018 12:16 am

Re: final review slide 4

Postby Owen-Koetters-4I » Sun Mar 15, 2020 1:06 pm

You subtract the mol of gas formed and the mol of gas reacting


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