## ∆U and ∆H

$\Delta U=q+w$

ng1D
Posts: 43
Joined: Wed Sep 18, 2019 12:17 am

### ∆U and ∆H

Why does when q = qP then ∆U = ∆H - P∆V?

Gabriella Bates 2L
Posts: 113
Joined: Thu Jul 11, 2019 12:15 am

### Re: ∆U and ∆H

By definition, qp = delta H. Therefore, under constant pressure, qp = delta H and w = P(delta V). We can then substitute these into the equation delta U = q + w, yielding delta U = delta H + P(delta V).

### Who is online

Users browsing this forum: No registered users and 1 guest