4D.3 Textbook


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Isis_DW_3G
Posts: 124
Joined: Wed Sep 30, 2020 10:04 pm

4D.3 Textbook

Postby Isis_DW_3G » Fri Mar 12, 2021 5:00 pm

when i did this question, i got q=-2.058kj, but i'm very confused as to why you have to go back and divide that by 1.40 grams (in moles) when the question was asking for the delta U of the reaction of 1mol
Can someone explain?
thanks!
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Lakshmi Davuluri 1E
Posts: 100
Joined: Wed Sep 30, 2020 9:50 pm

Re: 4D.3 Textbook

Postby Lakshmi Davuluri 1E » Fri Mar 12, 2021 5:22 pm

Hi, I'm not entirely sure if I understand your question, bu I think that the problem is asking for the delta U in regards to moles of CO specifically. So instead of just leaving it as -2.058 kJ, you need to divide that by the number of moles, which you get by converting the grams of CO to moles of CO. By doing this, you'll end up with the change in internal energy per mole of CO. Hope this helps!


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