Achieve HW #12


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Serena Sahota 1A
Posts: 31
Joined: Mon Jan 09, 2023 2:20 am

Achieve HW #12

Postby Serena Sahota 1A » Sun Feb 05, 2023 11:47 pm

How would I find C in the following problem?

At constant volume, the heat of combustion of a particular compound, compound A, is −3987.0 kJ/mol.
When 1.545 g
of compound A (molar mass =114.99 g/mol)
is burned in a bomb calorimeter, the temperature of the calorimeter (including its contents) rose by 5.497 ∘C.


What is the heat capacity (calorimeter constant) of the calorimeter?

Vishwa Diwan 1D
Posts: 36
Joined: Mon Jan 09, 2023 2:36 am

Re: Achieve HW #12

Postby Vishwa Diwan 1D » Mon Feb 06, 2023 10:01 am

Convert to the number of moles to find the correct q in the formula C=q/temp difference. Use the given -3987 to convert the number of moles to a number of kj being used and plug that into the C=q/change in temperature and that should get you C

George
Posts: 38
Joined: Mon Jan 09, 2023 2:35 am

Re: Achieve HW #12

Postby George » Tue Feb 07, 2023 8:56 pm

The heat capacity value is kJ/C thus in order to solve for it you should do −3987.0 kJ/mol * (1.545g *1 mol/114.99g)/5.497C. This will cancel all the unit and achieve the value of specific heat which is kJ per degree Celsius.


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