wk 6 hw 11


Moderators: Chem_Mod, Chem_Admin

206190205
Posts: 83
Joined: Fri Sep 29, 2023 10:42 am

wk 6 hw 11

Postby 206190205 » Fri Mar 15, 2024 2:09 pm

For a particular reaction, H + - 111.4 kj and S = -25.0 kj
Calculate G for this reaction at 298K.
I know that you have to use the equation G = H - TS, however i was trying to solve the equation and I set it all up and i feep on getting a different answer. I write -111.4 - 298(-25) and the answer is wrong. What am I doing wrong?

Maille Flynn 3H
Posts: 91
Joined: Fri Sep 29, 2023 11:02 am

Re: wk 6 hw 11

Postby Maille Flynn 3H » Fri Mar 15, 2024 2:16 pm

I think the problem is that H is given in kJ, while S is given in J/K. If you convert H to Joules this should fix it.

Ashley 3A
Posts: 81
Joined: Fri Sep 29, 2023 11:35 am

Re: wk 6 hw 11

Postby Ashley 3A » Fri Mar 15, 2024 2:20 pm

You have to make the units compatible. So you would do (111.4 kJ) - (298 K) (-25.0 J/K x 1kJ/1000). Convert delta s to kj per kelvin


Return to “Concepts & Calculations Using Second Law of Thermodynamics”

Who is online

Users browsing this forum: No registered users and 4 guests