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Does Boltzmann's equation account for entropy increase/decrease due to temperature? The only factor it has is microstates, so does that mean a molecule has the same entropy value a two different temperatures?
I believe that Boltzmann's Equation is used to find the residual positional entropy when the substance is at 0 Kelvin already.
The only factor in Boltzmann's entropy equation is microstate. In order for the arrangements of particles to give rise to the same total energy, the temperature has to be constant.
Boltzmann's equation works when the change in internal energy of the system is 0. So, if you were to change temperature, that would change the internal energy. What is possible though to find the entropy at two different energies and subtract them from eachother
I think Boltzmann's equation ignores thermal entropy altogether.
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