9.27a


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Mike Matthews 1D
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Joined: Fri Sep 29, 2017 7:04 am

9.27a

Postby Mike Matthews 1D » Mon Jan 29, 2018 10:26 pm

Homework 9.27a: Which substance has the higher molar entropy at 298K, HBr (g) or HF (g). Provided that both of these molecules have the same number of microstates, how does one determine the molar entropy difference between these two molecules?

Merzia Subhan 1L
Posts: 33
Joined: Thu Jul 13, 2017 3:00 am

Re: 9.27a

Postby Merzia Subhan 1L » Mon Jan 29, 2018 11:09 pm

I think it's because HBr(g) is larger than HF(g) so less compact and would therefore have a higher entropy. This may be wrong so if anyone has a different explanation, please share it.

Mitch Mologne 1A
Posts: 74
Joined: Fri Sep 29, 2017 7:04 am

Re: 9.27a

Postby Mitch Mologne 1A » Mon Jan 29, 2018 11:16 pm

More particles usually results in a higher entropy, which would explain why HBr (being the bigger molecule) has the higher entropy.

Riya Pathare 2E
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Re: 9.27a

Postby Riya Pathare 2E » Tue Jan 30, 2018 7:44 am

Since HBr is a larger compound than HF it will have more electrons that will be able to occupy more states thus giving it a higher entropy.

Janine Chan 2K
Posts: 71
Joined: Fri Sep 29, 2017 7:04 am

Re: 9.27a

Postby Janine Chan 2K » Tue Jan 30, 2018 11:01 pm

In general, more complex molecules will have higher entropy. Since HBr is larger than HF, it is more complex, has more particles (and thus more possible states it can exist in), and higher entropy.


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