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Posted: Mon Jan 29, 2018 10:26 pm
Homework 9.27a: Which substance has the higher molar entropy at 298K, HBr (g) or HF (g). Provided that both of these molecules have the same number of microstates, how does one determine the molar entropy difference between these two molecules?
Posted: Mon Jan 29, 2018 11:09 pm
I think it's because HBr(g) is larger than HF(g) so less compact and would therefore have a higher entropy. This may be wrong so if anyone has a different explanation, please share it.
Posted: Mon Jan 29, 2018 11:16 pm
More particles usually results in a higher entropy, which would explain why HBr (being the bigger molecule) has the higher entropy.
Posted: Tue Jan 30, 2018 7:44 am
Since HBr is a larger compound than HF it will have more electrons that will be able to occupy more states thus giving it a higher entropy.
Posted: Tue Jan 30, 2018 11:01 pm
In general, more complex molecules will have higher entropy. Since HBr is larger than HF, it is more complex, has more particles (and thus more possible states it can exist in), and higher entropy.