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9.27a

Posted: Mon Jan 29, 2018 10:26 pm
by Mike Matthews 1D
Homework 9.27a: Which substance has the higher molar entropy at 298K, HBr (g) or HF (g). Provided that both of these molecules have the same number of microstates, how does one determine the molar entropy difference between these two molecules?

Re: 9.27a

Posted: Mon Jan 29, 2018 11:09 pm
by Merzia Subhan 1L
I think it's because HBr(g) is larger than HF(g) so less compact and would therefore have a higher entropy. This may be wrong so if anyone has a different explanation, please share it.

Re: 9.27a

Posted: Mon Jan 29, 2018 11:16 pm
by Mitch Mologne 1A
More particles usually results in a higher entropy, which would explain why HBr (being the bigger molecule) has the higher entropy.

Re: 9.27a

Posted: Tue Jan 30, 2018 7:44 am
by Riya Pathare 2E
Since HBr is a larger compound than HF it will have more electrons that will be able to occupy more states thus giving it a higher entropy.

Re: 9.27a

Posted: Tue Jan 30, 2018 11:01 pm
by Janine Chan 2K
In general, more complex molecules will have higher entropy. Since HBr is larger than HF, it is more complex, has more particles (and thus more possible states it can exist in), and higher entropy.