9.23 (molar enthalpy between molecules)  [ENDORSED]


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Angela 1K
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9.23 (molar enthalpy between molecules)

Postby Angela 1K » Wed Jan 31, 2018 4:32 pm

The question asks: Which would you expect to have a higher molar entropy at T = 0, single crystals of BF3 or of COF2? Why?

The answer key says COF2, but I don't really understand its explanation for why. Could anyone rephrase the explanation or perhaps explain it in a different way in hopes that I'd be able to better understand it? Thanks.

Chem_Mod
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Re: 9.23 (molar enthalpy between molecules)  [ENDORSED]

Postby Chem_Mod » Wed Jan 31, 2018 4:38 pm

Here we more appropriately make use of the statistical definition of entropy:



where W = (# configurations)# components in the system. Since the molecule COF2 can be arranged in more unique orientations (configurations) than BF3, it has more entropy in a single crystal (no defects) at T = 0. This is called "residual entropy."

Natalie LeRaybaud 1G
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Re: 9.23 (molar enthalpy between molecules)

Postby Natalie LeRaybaud 1G » Wed Jan 31, 2018 8:53 pm

In addition, molecules that are considered more complex tend to have greater entropies. Since CoF2 can be arrange in more different orientations when compared to BF3, it is considered more complex and this has a greater entropy.


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