## 9.35 [ENDORSED]

$\Delta S = \frac{q_{rev}}{T}$

RyanTran2F
Posts: 44
Joined: Thu Jul 27, 2017 3:00 am

### 9.35

The answer key says, "The change in entropy for container A is greater than that for container B or C due to the greater number of particles." Is this saying container A has more particles? If so, how does container A have more particles? Thanks :)
Last edited by RyanTran2F on Sat Feb 03, 2018 9:16 pm, edited 1 time in total.

Lucian1F
Posts: 87
Joined: Fri Sep 29, 2017 7:07 am
Been upvoted: 1 time

### Re: 9.35

I believe it's saying that there are 1 mol of atoms in a, b, and c, but in b and c those atoms bind together to form diatomic molecules so then there are .5 moles of particles for b and c so a has the most particles.

David Minasyan 1C
Posts: 54
Joined: Thu Jul 13, 2017 3:00 am

### Re: 9.35

To put it another way, since b and c are bound they will have less disorder than the molecules that aren't so the entropy would be lower for those than say compared to the molecules that aren't bound to one another.

sahiltelang-Discussion 1J
Posts: 50
Joined: Thu Jul 13, 2017 3:00 am

### Re: 9.35

Pressure is a way of measuring the concentration of a gas in a certain volume. Therefore, B and C forms diatomic molecules and have less atoms and therefore less pressure in this problem in comparison to A.

Emily Mei 1B
Posts: 50
Joined: Fri Sep 29, 2017 7:04 am

### Re: 9.35

It is saying a has more molecules, and more molecules in a container means more entropy change.

Timothy Kim 1B
Posts: 62
Joined: Fri Sep 29, 2017 7:04 am

### Re: 9.35  [ENDORSED]

I believe this problem's solution is on the solution manual errors. A and C should have the same amount of disorder.