The sign of the change in Gibb's Free Energy


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John Huang 1G
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The sign of the change in Gibb's Free Energy

Postby John Huang 1G » Sun Feb 04, 2018 5:12 pm

Why is it that when the change in Gibb's Free Energy is negative, the process is considered thermodynamically favorable?

Jessica Jones 2B
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Re: The sign of the change in Gibb's Free Energy

Postby Jessica Jones 2B » Sun Feb 04, 2018 5:15 pm

This is because a negative G, corresponds to the reaction being spontaneous, and therefore favorable.

Rachel Brown 3A
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Re: The sign of the change in Gibb's Free Energy

Postby Rachel Brown 3A » Sun Feb 04, 2018 5:36 pm

To expand, if a reaction is spontaneous, it can occur more easily and often so it would be more favorable than a reaction that requires a specific environment and has a more difficult proceeding.

Christina Bedrosian 1B
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Re: The sign of the change in Gibb's Free Energy

Postby Christina Bedrosian 1B » Sun Feb 04, 2018 5:56 pm

when deltaG is negative, that means deltaS of the universe (total) is positive since deltaS(total)=-(deltaG)/T. deltaS being positive means the reaction is spontaneous (thus deltaG needs to be negative)

Amy Zheng 2l
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Re: The sign of the change in Gibb's Free Energy

Postby Amy Zheng 2l » Sun Feb 04, 2018 6:07 pm

Negative=spontaneous=no energy need to be added to do work

Veronica Rasmusen 2B
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Re: The sign of the change in Gibb's Free Energy

Postby Veronica Rasmusen 2B » Mon Feb 05, 2018 4:06 pm

When deltaG is negative it means the reaction is spontaneous, so it occurs easily and without work

Nicole Anisgard Parra 2H
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Re: The sign of the change in Gibb's Free Energy

Postby Nicole Anisgard Parra 2H » Mon Feb 05, 2018 10:04 pm

A negative value for Gibb's free energy indicates that no energy is needed to be added to the system to have the reaction occur spontaneously. Therefore, the reaction is spontaneous. If it was a positive value, that indicates that that quantity of energy must be added in order for the reaction to occur spontaneously, and therefore, it is not spontaneous.


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