DS= q/T for surroundings or system?
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DS= q/T for surroundings or system?
Can we use the equation DS = q/T for both the surroundings and the system?
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Re: DS= q/T for surroundings or system?
yep! So for instance, if heat is being released from System into Surroundings, System q will be negative and Surroundings q will be positive because the surroundings are absorbing heat. Further, System T should be higher than Surroundings T. These differing values will give you a different change in entropy value for the system versus the surroundings, unless its isothermal, which in that case it will just be opposite signs.
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Re: DS= q/T for surroundings or system?
Yes, I believe we can use that equation for calculating both ∆S for a system or its surroundings, but you would have to make sure the sign of q on the numerator matches the situation correctly.
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