## 9.5

$\Delta S = \frac{q_{rev}}{T}$

Kyra LeRoy 1E
Posts: 52
Joined: Sat Jul 22, 2017 3:00 am

### 9.5

I just wanted to double check if my train of thought was correct on this one:

Is the heat negative on the 800K reservoir because the process is taking heat from that reservoir and giving it to the 200K reservoir?
If not, why is it negative?

Thanks!

Manvir2K
Posts: 32
Joined: Fri Sep 29, 2017 7:05 am

### Re: 9.5

The heat is negative because 40.0 kJ of energy is being transferred from a large reservoir to another reservoir.

Rachel Formaker 1E
Posts: 86
Joined: Fri Sep 29, 2017 7:04 am
Been upvoted: 2 times

### Re: 9.5

Since the problem says that the heat is being transferred from one reservoir to another, you can assume that the heat is leaving the first reservoir (-q) and entering the second reservoir (+q).