∆S=q/T and irreversible reactions


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Xihui Yin 1I
Posts: 40
Joined: Fri Sep 29, 2017 7:06 am

∆S=q/T and irreversible reactions

Postby Xihui Yin 1I » Sat Feb 10, 2018 8:45 pm

Just to confirm, we can use q(rev)/T with the q value derived from an irreversible reaction since entropy is a state property right? I.e. use ∆H from an irreversible reaction to calculate q(rev). Are there any exceptions or stuff I have to take note?

Cynthia Tsang
Posts: 52
Joined: Fri Sep 29, 2017 7:07 am
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Re: ∆S=q/T and irreversible reactions

Postby Cynthia Tsang » Sat Feb 10, 2018 8:51 pm

yep, i think so.

Tiffany 1B
Posts: 32
Joined: Fri Sep 29, 2017 7:05 am

Re: ∆S=q/T and irreversible reactions

Postby Tiffany 1B » Sat Feb 10, 2018 8:53 pm

Yeah, since it's a state function the 'path' it took to get from initial to final doesn't matter so you could use the reversible path and that equation to solve for the irreversible. I think the book goes over this idea in more depth in the first few pages of chapter 9 as well. Hope that helps.


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