## ∆S=q/T and irreversible reactions

$\Delta S = \frac{q_{rev}}{T}$

Xihui Yin 1I
Posts: 40
Joined: Fri Sep 29, 2017 7:06 am

### ∆S=q/T and irreversible reactions

Just to confirm, we can use q(rev)/T with the q value derived from an irreversible reaction since entropy is a state property right? I.e. use ∆H from an irreversible reaction to calculate q(rev). Are there any exceptions or stuff I have to take note?

Cynthia Tsang
Posts: 52
Joined: Fri Sep 29, 2017 7:07 am
Been upvoted: 1 time

### Re: ∆S=q/T and irreversible reactions

yep, i think so.

Tiffany 1B
Posts: 32
Joined: Fri Sep 29, 2017 7:05 am

### Re: ∆S=q/T and irreversible reactions

Yeah, since it's a state function the 'path' it took to get from initial to final doesn't matter so you could use the reversible path and that equation to solve for the irreversible. I think the book goes over this idea in more depth in the first few pages of chapter 9 as well. Hope that helps.