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delta S for reversible and irreversible reactions

Posted: Thu Mar 15, 2018 5:56 pm
by Hannah Guo 3D
Can someone explain why deltaS(tot, rev)=0, but deltaS(tot, irri)>0 ?

Re: delta S for reversible and irreversible reactions

Posted: Fri Mar 16, 2018 9:10 pm
by Michaela Capps 1l
When it is reversible, the system is at equilibrium so it =0. When deltaS >0 the reaction is spontaneous, which is a part of the second law of thermodynamics