## Practice Midterm

$\Delta S = \frac{q_{rev}}{T}$

Jesse_torres2H
Posts: 41
Joined: Thu Jul 27, 2017 3:00 am

### Practice Midterm

From the practice midterm question 6a reads we can expect an endothermic reaction to be favorable at a very hight temp. Why would this be false?

Diane Bui 2J
Posts: 61
Joined: Sat Jul 22, 2017 3:00 am

### Re: Practice Midterm

It is false because we do not know the value of delta S.
Endothermic means that delta H is positive. According to the gibbs free energy equation (delta G = delta H - TdeltaS), an endothermic reaction would be favorable at a high temp if delta S was positive as well. If delta S was negative and delta H was positive, then the reaction would never be favorable.

Justin Bui 2L
Posts: 51
Joined: Fri Sep 29, 2017 7:06 am

### Re: Practice Midterm

Yeah, I agree with what Diane said but I feel like it being completely false is a little unfair of a generalization. I think a lot of the time delta S happens to be positive so it is true that an endothermic reaction is favorable at high temperatures but it is true that negative entropy would throw that all off.