7th edition 4F.9


Moderators: Chem_Mod, Chem_Admin

Post Reply
Maggie Doan 1I
Posts: 61
Joined: Fri Sep 28, 2018 12:24 am

7th edition 4F.9

Postby Maggie Doan 1I » Wed Feb 06, 2019 11:35 pm

Calculate the change in entropy when the pressure of 1.5mol Ne(g) is decreased isothermally from 15.0 atm to .500 atm. Assume ideal behavior.
Top
ThomasLai1D
Posts: 61
Joined: Fri Sep 28, 2018 12:17 am

Re: 7th edition 4F.9

Postby ThomasLai1D » Thu Feb 07, 2019 10:28 am

From the equation delta S= nRln(V2/V1), using Boyle's law P1V1=P2V2, derive the equation delta S =nRln(P1/P2), and plug the values in.

1.50mol x 8.314 J/mol/K x ln(15.0atm/0.500atm)=42.4 J/K
Top
Post Reply

Return to “Concepts & Calculations Using Second Law of Thermodynamics”

Who is online

Users browsing this forum: No registered users and 17 guests