ΔS=q/t

[Tamera Scott 1G]

When looking at the equation ΔS=q/t, could we say that ΔS=nΔH/T as well?

[Nicole Lee 4E]

ΔS=ΔH/T at constant pressure and temperature.

[haleyervin7]

What are the requirements to be able to use q/T? Just constant temp?

[AdityaGuru1H]

you can use it when t is constant and you can use deltaS=DeltaH/T when pressure is constant

[ran2000]

This can only be said when pressure is constant since q(at constant pressure)= delta H

[Nicholas Le 4H]

Yes, you can use this when pressure is constant since the change in enthalpy is equal to q when pressure is constant.

[Soumya Ravichandran 4H]

Why can you only calculate delta S, when the q for the reaction is reversible?

[Dayna Pham 1I]

Why can you only calculate delta S, when the q for the reaction is reversible?

The reaction does not have to be reversible in order to calculate delta S in this way. They just use q rev as a convention, but since delta S is a state function, the pathway doesn’t matter (therefore, it doesn’t matter if it’s reversible or reversible). The only thing we look at is final - initial. Which would be the same for irreversible and reversible.

[Ashe Chen 2C]

when pressure and temperature are constant,