## Efficiency

Boltzmann Equation for Entropy: $S = k_{B} \ln W$

Moderators: Chem_Mod, Chem_Admin

SanthosiSamudrala14B3K
Posts: 12
Joined: Fri Sep 25, 2015 3:00 am

### Efficiency

Why is it more efficient to have a reversible reaction compared to a irreversible reaction? Since less work is used in an irreversible reaction, I don't understand why it isn't more efficient.

Nathan Danielsen 1G
Posts: 17
Joined: Fri Sep 25, 2015 3:00 am

### Re: Efficiency

When a reaction is efficient, all the heat produced by the reaction is used to do work. An irreversible reaction does less work because some of the heat produced by the reaction leaves the system. In a reversible reaction, all the energy produced by the reaction is used to do work, which is why they tend to do more of it. Energy leaving the system as heat is assessed as inefficiency, so an irreversible reaction in which none of the energy escapes is perfectly efficient.

Return to “Third Law of Thermodynamics (For a Unique Ground State (W=1): S -> 0 as T -> 0) and Calculations Using Boltzmann Equation for Entropy”

### Who is online

Users browsing this forum: No registered users and 1 guest