H2(g) --> H2(g)

Boltzmann Equation for Entropy:

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Emily Glaser 1F
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Joined: Thu Jul 27, 2017 3:01 am

H2(g) --> H2(g)

Postby Emily Glaser 1F » Sun Feb 11, 2018 6:23 pm

Let's say we have H2(g) in some larger equation and we are attempting to determine the delta G for this rxn. Exluding the other products and reactants, I want to look at just changes in the values associated with H2.

Would the standard enthalpy of formation be zero?
Would the standard molar entropy be 0 (or 130.6 as I found in the Appendix)
Would delta G be zero or -130.6?

Ozhen Atoyan 1F
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Joined: Thu Jul 27, 2017 3:01 am
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Re: H2(g) --> H2(g)

Postby Ozhen Atoyan 1F » Sun Feb 11, 2018 6:34 pm

The answer to your first question would be yes, the enthalpy of formation for H2 would be 0, because it is diatomic.

Yang Chen 2E
Posts: 36
Joined: Thu Jul 13, 2017 3:00 am

Re: H2(g) --> H2(g)

Postby Yang Chen 2E » Sun Feb 11, 2018 9:14 pm

I don't think delta G will be zero as you said you are only referring to H2. Delta G can only be applied to processes like phase changes or reactions.

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