winter 2012 midterm question 3A

Boltzmann Equation for Entropy:

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704278444
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winter 2012 midterm question 3A

Postby 704278444 » Mon Feb 10, 2014 5:50 pm

How do you determine W (microstates)of BH2F and O2?
In the answer:
W for BH2F=3, is it because that B forms three bonds?
and How is W for O2 is 1?
Thanks!

Chem_Mod
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Re: winter 2012 midterm question 3A

Postby Chem_Mod » Mon Feb 10, 2014 9:17 pm

Consider the number of ways you could arrange 2 bonds in 3 spaces, i.e. 3!/(2!(3-2)!) = 3
O2 has only one bond and therefore only one configuration, so W = 1

Lauren Ton 4B
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Re: winter 2012 midterm question 3A

Postby Lauren Ton 4B » Tue Feb 10, 2015 9:01 pm

Why do you consider only 2 bonds for the three spaces? Can you go into more depth for the explanation for why W=3 for BH2F?

Neil DSilva 1L
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Re: winter 2012 midterm question 3A

Postby Neil DSilva 1L » Thu Feb 12, 2015 12:00 am

This is how I visualized finding W for BH2F. There's three possible states and only one molecule, so W = 3.
Attachments
FullSizeRender.jpg
W for BH2F


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