4G.5 7th edition

Boltzmann Equation for Entropy:

Moderators: Chem_Mod, Chem_Admin

Samantha Chung 4I
Posts: 77
Joined: Wed Oct 03, 2018 12:16 am

4G.5 7th edition

Postby Samantha Chung 4I » Wed Feb 06, 2019 8:45 am

For ths question, how do I tell the number of possible orientations for degeneracy in both molecules? For a molecule like Ch3Cl that was given in class, I know that it is 4^N, but how do I tell the number of possible orientations for a trigonal bypyramidal structure?

Camille Marangi 2E
Posts: 60
Joined: Fri Sep 28, 2018 12:26 am

Re: 4G.5 7th edition

Postby Camille Marangi 2E » Wed Feb 06, 2019 9:14 am

The possible orientations just depend on the atoms involved. For example, CH4 is a tetrahedral just like CH3Cl but only has one possible state to be found in and thus its degeneracy is seen as w=1^n. So this logic would follow with a trigonal bipyramidal- if the atoms attached to the central atom are all the same then there is only one possible state.

Return to “Third Law of Thermodynamics (For a Unique Ground State (W=1): S -> 0 as T -> 0) and Calculations Using Boltzmann Equation for Entropy”

Who is online

Users browsing this forum: No registered users and 2 guests