## HW Prolem (4G.4) 7th Edition

Boltzmann Equation for Entropy: $S = k_{B} \ln W$

Helen Mejia 1I
Posts: 67
Joined: Fri Sep 28, 2018 12:24 am

### HW Prolem (4G.4) 7th Edition

Can someone explain how to identify which of BF3 or COF2 will have a higher molar entropy?

Xuan Kuang 2L
Posts: 31
Joined: Wed Nov 14, 2018 12:23 am

### Re: HW Prolem (4G.4) 7th Edition

COF2 would have a higher molar entropy than BF3.

When you take a look at the molecular structures, BF3 is a trigonal planar with the same B-F bond on each end. This means that is it very ordered, compared to COF2, which has two F's and an O at the ends. This means that for some molecules, it could possibly have an F or an O at a specific end, so it is less ordered because not every end is identical. Thus, COF2 has a higher molar entropy.

Laura Gong 3H
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Joined: Fri Sep 28, 2018 12:26 am
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### Re: HW Prolem (4G.4) 7th Edition

COF2 has greater molecular complexity compared to BF3 which means it has a greater number of possible positions/orientations which makes its entropy greater than BF3 which has lesser number of possible positions.

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