HW Prolem (4G.4) 7th Edition
Moderators: Chem_Mod, Chem_Admin
-
- Posts: 67
- Joined: Fri Sep 28, 2018 12:24 am
HW Prolem (4G.4) 7th Edition
Can someone explain how to identify which of BF3 or COF2 will have a higher molar entropy?
-
- Posts: 31
- Joined: Wed Nov 14, 2018 12:23 am
Re: HW Prolem (4G.4) 7th Edition
COF2 would have a higher molar entropy than BF3.
When you take a look at the molecular structures, BF3 is a trigonal planar with the same B-F bond on each end. This means that is it very ordered, compared to COF2, which has two F's and an O at the ends. This means that for some molecules, it could possibly have an F or an O at a specific end, so it is less ordered because not every end is identical. Thus, COF2 has a higher molar entropy.
When you take a look at the molecular structures, BF3 is a trigonal planar with the same B-F bond on each end. This means that is it very ordered, compared to COF2, which has two F's and an O at the ends. This means that for some molecules, it could possibly have an F or an O at a specific end, so it is less ordered because not every end is identical. Thus, COF2 has a higher molar entropy.
-
- Posts: 89
- Joined: Fri Sep 28, 2018 12:26 am
- Been upvoted: 1 time
Re: HW Prolem (4G.4) 7th Edition
COF2 has greater molecular complexity compared to BF3 which means it has a greater number of possible positions/orientations which makes its entropy greater than BF3 which has lesser number of possible positions.
Who is online
Users browsing this forum: No registered users and 1 guest