9.25 6th edition

Boltzmann Equation for Entropy:

Moderators: Chem_Mod, Chem_Admin

Esther Lee 4H
Posts: 67
Joined: Fri Sep 28, 2018 12:29 am

9.25 6th edition

Postby Esther Lee 4H » Tue Feb 19, 2019 9:36 pm

9.25: if SO2F2 adopts a positionally disordered arrangement in its crystal form, what might its residual molar entropy be?

I know you use the S=Kb*ln(W) equation and that it has 6 possible orientations but how would I know how many molecules are in it? the answer book says ln(6^6.02x10^23) but where did they get the 6.02x10^23?

Mindy Kim 4C
Posts: 65
Joined: Fri Sep 28, 2018 12:25 am

Re: 9.25 6th edition

Postby Mindy Kim 4C » Tue Feb 19, 2019 9:40 pm

Since the question asks for residual molar entropy, they are asking for the residual entropy for one mole of SOF2. There are 6.022x10^23 molecules (Avogadro's number) in one mole.

Esther Lee 4H
Posts: 67
Joined: Fri Sep 28, 2018 12:29 am

Re: 9.25 6th edition

Postby Esther Lee 4H » Tue Feb 19, 2019 9:43 pm

Mindy Kim 4C wrote:Since the question asks for residual molar entropy, they are asking for the residual entropy for one mole of SOF2. There are 6.022x10^23 molecules (Avogadro's number) in one mole.

ohhh that makes a lot of sense thank you


Return to “Third Law of Thermodynamics (For a Unique Ground State (W=1): S -> 0 as T -> 0) and Calculations Using Boltzmann Equation for Entropy”

Who is online

Users browsing this forum: No registered users and 1 guest