Boltzmann Equation for Entropy:

Moderators: Chem_Mod, Chem_Admin

Junwei Sun 4I
Posts: 125
Joined: Wed Oct 02, 2019 12:16 am


Postby Junwei Sun 4I » Thu Feb 06, 2020 10:16 pm

The question is:

Considering positional order, would you expect a crystal of octahedral cis-MX2Y4 to have the same, higher, or lower residual entropy than the corresponding trans isomer? Explain your conclusion.

The solution manual says that cis-MX2Y4 has 12 orientations whereas the trans isomer only has 3 and that's the part that I don't understand. Could someone please explain why there are 12 orientations? Thanks!

Connie Chen 1E
Posts: 51
Joined: Mon Jun 17, 2019 7:24 am

Re: 4G.5

Postby Connie Chen 1E » Fri Feb 07, 2020 10:13 am

There are 12 orientations because in a cis- isomer, the X's must be adjacent to each other, or 90 degrees from each other in this case. With the octahedral cis-MX2Y4, there are 12 different ways for the two X's to be next to each other.

Return to “Third Law of Thermodynamics (For a Unique Ground State (W=1): S -> 0 as T -> 0) and Calculations Using Boltzmann Equation for Entropy”

Who is online

Users browsing this forum: No registered users and 1 guest