4G.5

Boltzmann Equation for Entropy:

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Junwei Sun 4I
Posts: 125
Joined: Wed Oct 02, 2019 12:16 am

4G.5

Postby Junwei Sun 4I » Thu Feb 06, 2020 10:16 pm

The question is:

Considering positional order, would you expect a crystal of octahedral cis-MX2Y4 to have the same, higher, or lower residual entropy than the corresponding trans isomer? Explain your conclusion.

The solution manual says that cis-MX2Y4 has 12 orientations whereas the trans isomer only has 3 and that's the part that I don't understand. Could someone please explain why there are 12 orientations? Thanks!

Connie Chen 1E
Posts: 51
Joined: Mon Jun 17, 2019 7:24 am

Re: 4G.5

Postby Connie Chen 1E » Fri Feb 07, 2020 10:13 am

There are 12 orientations because in a cis- isomer, the X's must be adjacent to each other, or 90 degrees from each other in this case. With the octahedral cis-MX2Y4, there are 12 different ways for the two X's to be next to each other.


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