Avogadro's Number in Calculations

Boltzmann Equation for Entropy:

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SelenaDahabreh1D
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Avogadro's Number in Calculations

Postby SelenaDahabreh1D » Wed Feb 17, 2021 1:35 pm

I've seen some questions where when calculating degeneracy, W, the value is put to a power of Avogadro's number. When exactly do we do this?

Benjamin Chen 1H
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Re: Avogadro's Number in Calculations

Postby Benjamin Chen 1H » Wed Feb 17, 2021 3:54 pm

You would probably use this when there is 1 mole of molecules. For instance if you have 2 state possible for every molecule and you have 2 molecules, then W = 2^2. When you have 1 mole of the molecules, W = 2^(6.022x10^23).

shevanti_kumar_1E
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Re: Avogadro's Number in Calculations

Postby shevanti_kumar_1E » Wed Feb 17, 2021 5:13 pm

You use avagadro's number to calculate W when it tells you the moles of particles. You would use avagadro's number to convert moles into particles and then plug that into the equation. Textbook problem 4G.5 is a good example of how you would use avagadro's number to help you find the degeneracy.

Emmeline Phu 1G
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Re: Avogadro's Number in Calculations

Postby Emmeline Phu 1G » Wed Feb 17, 2021 5:28 pm

Hi! When calculating degeneracy, you would use avagadro's number when there is one mole of substance. Since one mole is equal to 6.022x10^23 molecules, you can substitute avagadro's number for the number of particles in the degeneracy calculation. Hope this helps! :)

Susanna Givan 2B
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Re: Avogadro's Number in Calculations

Postby Susanna Givan 2B » Sun Mar 14, 2021 11:11 pm

You do it when you don't know the number of molecules there are, right? Like when it gives you moles or another value?


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