## 9.43

Volume: $\Delta S = nR\ln \frac{V_{2}}{V_{1}}$
Temperature: $\Delta S = nC\ln \frac{T_{2}}{T_{1}}$

Dahriel Aron 3A
Posts: 60
Joined: Fri Sep 25, 2015 3:00 am

### 9.43

for this question it says that 50g h20 at 20 degrees celsius is mixed with 65g of h20 at 50 degrees celsius and wants delta s and delta s total. In the solutions manual it uses q=-q and uses 75.3 for the specific heat. I was wondering where the number 75.3 comes from

Chem_Mod
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### Re: 9.43

That is the molar heat capacity. (4.18J/gm.Kelvin) x (18gm/mole) = 75.24J/mole.Kelvin