Winter 2015 Midterm 4B

Volume:
Temperature:

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Rhea Palsule
Posts: 22
Joined: Fri Sep 25, 2015 3:00 am

Winter 2015 Midterm 4B

Postby Rhea Palsule » Mon Feb 08, 2016 10:40 pm

In the problem, the volume is expanding from 3.3L to 9.2*10^5 L. However, when calculating the heat capacity for step 2, the solution says that volume is constant and C= 3/2(R). Shouldn't it be 5/2(R) because the pressure is constant?

Jamlah Dalie 1K
Posts: 62
Joined: Fri Sep 25, 2015 3:00 am

Re: Winter 2015 Midterm 4B

Postby Jamlah Dalie 1K » Mon Feb 08, 2016 11:07 pm

Since it doesn't state anywhere in the problem that the pressure is held constant while all this is happening, we can't assume it. So in the second part since we already accounted for the change in volume and we're accounting for the change in temperature now, we can assume that the volume is held constant, which is why we use 3/2 rather than 5/2.


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