Ch 8 Exercise 41

Volume:
Temperature:

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Ariana_Kermani_2G
Posts: 10
Joined: Fri Jul 15, 2016 3:00 am

Ch 8 Exercise 41

Postby Ariana_Kermani_2G » Tue Feb 14, 2017 9:58 pm

A 50.0g ice cube at 0.0 degrees Celsius is added to a glass containing 400.0g of water at 45.0 degrees Celsius. What is the final temperature of the system? Assume that no heat has been lost to the surroundings.

Why do we use this equation to solve the problem? And why are the equations set equal to one another? :
[(m)(specific heat)(delta T)]+[(n)(delta H of fusion) of ice]=[-(m)(specific heat)(delta T) of water]

csebastiani_1B
Posts: 15
Joined: Wed Sep 21, 2016 2:59 pm

Re: Ch 8 Exercise 41

Postby csebastiani_1B » Tue Feb 14, 2017 10:02 pm

They are set equal to each other because the heat lost by the water goes to the ice. Also i think they are equal to each other with a negative sign like this -q(ice)=q(water)


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