Volume: $\Delta S = nR\ln \frac{V_{2}}{V_{1}}$
Temperature: $\Delta S = nC\ln \frac{T_{2}}{T_{1}}$

Lizzie Zhang 2C
Posts: 31
Joined: Fri Sep 29, 2017 7:05 am

It says in the book section 9.7, S(T)=S(0)+deltaS(heating from 0 to T)=deltaS(heating from 0 to T)
Why it can be equaled that way? Since S(0) is only 0 for perfect crystals at T=0?
If it's not a perfect zero, wouldn't S(0) be some number due to the positional entropy?

Emily Oren 3C
Posts: 50
Joined: Fri Sep 29, 2017 7:07 am

### Re: About entropy at T=0

I think that either this equation is assuming that the substance is a perfect crystal or that it is an approximation and that the positional entropy of the substance at 0K is negligible when compared with the deltaS term.